Ponder this one

The formula for adding velocities in "Relativities"

v' is the velocity of the man in the train frame of reference

v is the velocity of the train in the ground frame of reference
r

v is the velocity of the man in the ground frame of reference

c is the speed of light

then

v' + v
r
v = --------------
1 + v' v / c^2
r
 
So now to plug the numbers in

C = 670,680,000 mph

v' = 6 mph

vr = 670,679,995 mph

solving for "v"


v =

(6 mph + 670,679,995 mph) / ( 1 + (6 mph)*((670,679,995 mph) / (670,680,000 mph)^2)


and after some long computing....

v = 670,679,995.00003

Which is less than 670,680,001 that you would logically come up with..
 
I don't know about your equations, but I believe the man would be able to walk

Relativity is exclusive to your perspective

to the man he is moving 6 miles per hour and everything is fine

to a bystandard he can only ever Look to be moving as fast as the speed of light
then possibly frozen in time but only to an outside perspective
 
Re: RE: Ponder this one

Ryum said:
I don't know about your equations, but I believe the man would be able to walk

Relativity is exclusive to your perspective

to the man he is moving 6 miles per hour and everything is fine

to a bystandard he can only ever Look to be moving as fast as the speed of light
then possibly frozen in time but only to an outside perspective
Click to expand...

Well, it all depends on what theory's you apply to it. And the theory I'm applying states that "nothing can move faster than the speed of light"
 
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