Light hearted debate for the non-debaters.

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Question - can a plane take off from a conveyor belt/treadmill assuming the treadmill/conveyor belt able to support the plane's weight and match its speed?

I put it to you that a plane can in fact take off from such a contraption given that the thrust acts against the air rather than the ground. What say ye?







(This has been done a number of times I'm sure at various places/forums. I'm not sure if it's been done here (searched just once with a couple of terms) but feel free to merge if it has.)
 
Unfortunately I can't get past the comical image of a plane-sized treadmill or a treadmill-sized plane to think this through logically. My gut says it's a stupid idea because if it were possible, they'd already be doing it to save all that blasted runway space.
 
Yes the plane will fly.

Consider the following:
A plane is powered by jet propulsion or by propeller not by the wheels, a car is, so a car with wings would just sit there and never gain foward movement. But, as the plane pushes the air behind it, it will gain foward momentum regardless of what speed the belt or wheels are doing beneath it. This will cause the foward speed of the plane increases until lift is achieved. The speed of the belt driven runway would increase exponentially until the plane left the surface trying to match the speed of the unfettered plane.

A plane only requires air speed to maintain lift and regardless of the relative speed of the motorized runway beneath it, it will reach that designated air speed via rear thrust as long as there are no other forces holding it in place (ie. cable or chain)


Here's what I said about this topic back in 2005
 
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