Your age

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Zorak

Zorak

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COOL_BREEZE2 said:
Don't tell me your age; you probably would tell a falsehood anyway-but
Your waiter may know!

YOUR AGE BY DINER & RESTAURANT MATH

DON'T CHEAT BY SCROLLING DOWN FIRST!

It takes less than a minute. Work this out as you read .

Be sure you don't read the bottom until you've worked it out!

This is not one of those waste of time things, it's fun.


1. First of all, pick the number of times a week that you would like to

Go out to eat.

(more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5

4. Multiply it by 50

5. If you have already had your birthday this year add 1758...

If you haven't, add 1757.

6. Now subtract the four digit year that you were born.

You should have a three digit number


The first digit of this was your original number. (I.e., How many times
You want to go out to restaurants in a week.)


The next two numbers are



YOUR AGE ! ------ (Oh YES, it is!)



THIS IS THE ONLY YEAR (2008) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE
IT LASTS
Click to expand...


(((x*2+5)*50)+[[1757] or [1758]])-[birth year]

Now, why does it work?

well, let us use a little algebra on the first part (x*2 + 5)*50, to simplify it:

distibution of the 50 to both the x*2 and 5 terms:
50x*2 + 50(5)

multiply the 50 * 2 to get 100, then multiply by unknown x (100x) and 50*5 is 250
100x + 250;

do the choice, for me it is 1987 with birthday already occurred, so 1758:

100x + 250 + 1758 - 1987; collect and simplify terms

100x + 250 + -229

100x - 21

you will immediately notice something (if you are a math wizard, you may have noticed it in the original word problem), and that is that the word problem (test, if you will, of the idea) is worded incorrectly:

Now subtract the four digit year that you were born
Click to expand...

It should read:

Now subtract the result from the four digit year that you were born
Click to expand...

which would produce the correct sign on the last term, as such:

100x + 21;

The year 2008, as demonstrated, has absolutely nothing to do with the problem at hand, being that it is never used. The year is only to get the recipient to feel rushed to spread it around, but it is in fact, an unnecessary piece of the puzzle, unneeded thing in the word problem.

Therefore, it could be stated that 2050 would be the only year it could be done, but the numbers will not change...

This problem could have been done 29.38 billion years ago, and the result would have been the same.

Now, to get back to how it works:

Pick a number between zero and ten (100x, where x=0 would result in 0 + 21; 100x, where x=10 would result in 1000 + 21); the digits 1-9 are not "place-changers", in that, when multiplied by a power of ten, will have the same digit, but in the n-th position (10^n).

The other important factor is how to get to the 10^n, as well as the interesting 1758/1757 number (subtract the 5+50 stuff); mostly used during number theory.

In fact, all this *is* number theory, disguised as a game.

Not spectacular at all.
 
Zorak

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i'm so fucking confused i poured myself another glass of wine and rolled another joint. i hope you happy.
 
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I forgot to mention that the year part is something called "social engineering," a type of phenomenon that induces people to do something, based on something else; such as attempting to get people to download a particular virus software (in these cases, most of the time the downloaded software *is* a virus or other malicious program), or in this case, try something that seems novel, but will work for a limited time only.
 
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Zorak said:
i'm so fucking confused i poured myself another glass of wine and rolled another joint. i hope you happy.
Click to expand...

Don't worry, it was a lot of number theory and algebra; I almost got confused with the signs thing.

What kind of wine?

I am a total wine noob, and would not mind learning about it before that big first big dinner. :nod:
 
Zorak

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Merlot

Merlot is a very generic sort of red wine, the grape is typically quite thick skinned and resiliant so a lot of countries grow it.
A lot of wine tasters and 'experts' look down on Merlot I have to admit, but personally while I admit while Merlot can lack some extravagence and flavour at the most expensive levels, when it comes to affordable wine it is a god send.
Because it can be full and fruity and really tasty, and it it is only the most discerning pallet that will taste the imperfections in Merlot.
 
COOL_BREEZE2

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ssl said:
(((x*2+5)*50)+[[1757] or [1758]])-[birth year]

Now, why does it work?

well, let us use a little algebra on the first part (x*2 + 5)*50, to simplify it:

distibution of the 50 to both the x*2 and 5 terms:
50x*2 + 50(5)

multiply the 50 * 2 to get 100, then multiply by unknown x (100x) and 50*5 is 250
100x + 250;

do the choice, for me it is 1987 with birthday already occurred, so 1758:

100x + 250 + 1758 - 1987; collect and simplify terms

100x + 250 + -229

100x - 21

you will immediately notice something (if you are a math wizard, you may have noticed it in the original word problem), and that is that the word problem (test, if you will, of the idea) is worded incorrectly:



It should read:



which would produce the correct sign on the last term, as such:

100x + 21;

The year 2008, as demonstrated, has absolutely nothing to do with the problem at hand, being that it is never used. The year is only to get the recipient to feel rushed to spread it around, but it is in fact, an unnecessary piece of the puzzle, unneeded thing in the word problem.

Therefore, it could be stated that 2050 would be the only year it could be done, but the numbers will not change...

This problem could have been done 29.38 billion years ago, and the result would have been the same.

Now, to get back to how it works:

Pick a number between zero and ten (100x, where x=0 would result in 0 + 21; 100x, where x=10 would result in 1000 + 21); the digits 1-9 are not "place-changers", in that, when multiplied by a power of ten, will have the same digit, but in the n-th position (10^n).

The other important factor is how to get to the 10^n, as well as the interesting 1758/1757 number (subtract the 5+50 stuff); mostly used during number theory.

In fact, all this *is* number theory, disguised as a game.

Not spectacular at all.
Click to expand...

Thanks ssl. That is so much clearer now. My head hurts now though. :D

And the frightening thing is that I bet that came to you naturally. Like 1 + 1 = 2. :nod:
 
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Zorak:

Thanks for the suggestion. I shall try some soon. :)

COOL_BREEZE2:

Here is some more food for thought:

How do you want me to interpret the + symbol? Addition or connotation?

1 + 1 = 2 or 11

:ninja.

:D

Actually, no. The thought only occurred when I thought about why it might work. Then I realized the year had nothing to do with it, then I knew there was some fun number crunching behind it. :)
 
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There are some subjects I could bore myself out by talking about them, others I pay attention to those that know more, and still others I care not to pay too much attention to, although sometimes there may be cross-information/ideas that might be fruitful.

:)
 
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